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lesson

Index of the maximum

objective: debugging exercise · lists & indexing · medium

Task type: fix broken code

index_of_max(nums) should return the position of the largest number in the list — not the number itself.

fix this code so it matches

index_of_max([3, 7, 2]) is 1 (7 is at index 1). index_of_max([9, 1, 2]) is 0. index_of_max([5]) is 0.

○Passes the visible tests
○Passes the hidden tests (edge cases)

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index_of_max.pyattempt 0

def index_of_max(nums):    best_value = nums[0]    for i in range(len(nums)):        if nums[i] > best_value:            best_value = nums[i]    return best_value